Engineering Homework Help

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Thread 1

   This week have been a challenge in the circuitry subject. I was able to successfully build my circuit after many failures and now I get to briefly describe it. To begin, we all know electricity in a circuit begins at the source and I choose to supply my lightbulb with 5V. Immediately after my power source I installed an inductor to ensure no reverse current is present in the circuit. I choose the basic measurement of (H) Henry for my value. Latter down the circuit I installed my two resistors with a value of 100 ohms each. Now, like many electronic devices nowadays, a capacitor is used to stored current (Kenny, 2013). My capacitor has a value of 5 GF. Lastly, the light bulb was installed at the end of the circuit and after close examination of my values across the entire circuit, I was able to successfully power it without burning out. I have included a multimeter for my fellow classmates to be able to “tinker” with the circuit as you all please and provide constructive feedback that could help me better my circuit. As I mentioned in the beginning of this post, this assignment was a real challenge and up to this point I still would like to see what type of feedback I will receive and hopefully I can broaden my understanding further into this subject.

Thread 2 

My compound circuit is below. I have a Function Generator supplying 10 Volts AC at 400 Hertz, 1 Inductor at 5 Inductance, 1 Resistor set at 100 Ohms, 1 Resistor set at 50 Ohms, and LED, 2 Switches, 1 Ammeter and 2 Voltmeters. On the right side, I have the parallel section, with red wires. One leg of the parallel section goes through both resistors and the inductor. The other goes ‘through’ the capacitor. The capacitor doesn’t allow current to travel through it, but rather builds up a charge and discharges it, serving similarly to a primer when power is applied to the circuit. 

 The voltmeter on the right reads at 3.3 Volts AC, meaning a drop in 3.3 volts across the resistors and inductor. The voltmeter on the left reads at 1.75 volts AC, meaning that the LED is converting 1.75 volts into light. The ammeter is isolated from the circuit by the 2 switches. If you turn off the upper switch and turn on the lower switch, the ammeter will read 33.4 amps. (volts must be measured with the switches in the opposite configuration) The reason for this circuit is that voltage must be measured in parallel, and amps in series. Therefore, you must reconfigure the circuit to measure one or the other. “An ammeter becomes a voltmeter when a resistance is placed in series with the meter coil and the current is measured through it.” (Kenney, 2013) Current flowing through the LED is 21.4 mA, which is apparently higher than recommended.